nu bagati in seama cerinta cu nr nat nenule,DAU COROANA
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Răspuns:
[tex] {1 }^{2} + {2}^{x } + {3}^{y } < 4[/tex]
REZOLVARE:
[tex] {1}^{2} + {2}^{1 } + {3}^{0} < 4[/tex]
[tex]1 + 2 + 0 < 4[/tex]
[tex]3 < 4[/tex]