Răspuns:
[tex]a_1=\frac{3}{2}\\\\a_2 =\frac{2}{3}[/tex]
Explicație pas cu pas:
[tex]\frac{a^2+1}{a}=\frac{13}{6}\ => 6a^2+6=13a\ =>\ 6a^2-13a+6=0\\\\delta=b^2-4ac=169-144=25\\\\a_1=\frac{13+5}{12}=\frac{18}{12}=\frac{3}{2}\\\\a_2=\frac{13-5}{12}=\frac{8}{12}=\frac{2}{3}[/tex]
