Răspuns:
y=2sin10t
elongatia la momentul t1,Mai intai determinam perioada T
T=2π/ω ω=10
T=2π/10=π/5
t1=(π/5)/12=π/60
y=2sin10/π60=
2sinπ/6=2*1/2=1
viteza
v=2*10cos 1ot
v=20cos10*π/60=
20 cosπ/6=20*√3/2=10√3cm /s
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a=-ω²A sinωt1
a=-10²*2 sin 10π/60=
-100*2 sinπ/6=
-200*1/2= -100cm/s²²
Explicație:
