1) Scrii reactia
Zn + 2 HCl ---> ZnCl2 + H2
2) Calculezi masa molara pt HCl
HCl = 1+35,5 = 36,5 g/mol
3)Calculezi masa de HCl
65 g Zn.........2*36,5 g HCl
1300 g Zn............x g HCl x = 1460 g HCl
4)Calculezi masa solutiei
ms = md/c * 100 = 1460/35 * 100 = 4147,429 g
5)Calculezi volumul solutiei
ro = m/V => V = 4171.429/1,04 = 4011 cm cubi = 4,011 l