[tex]a= \frac{1}{\sqrt{5}+1}= \frac{\sqrt{5}-1}{5-1}= \frac{\sqrt{5}-1}{4} \\ \\ \\ b=\sqrt{15}:\sqrt{3}+1 \\ b=\sqrt{5}+1 \\ \\ mg=\sqrt{ab}= \sqrt{\frac{\sqrt{5}-1}{4}*(\sqrt{5}+1)}= \\ \\ \\ =\sqrt{\frac{5-1}{4}}=\sqrt{\frac{4}{4}}=\sqrt{1}=1[/tex]
