2 NaCl + 2 H2O ---> 2 NaOH + H2 + Cl2
md1=1000*29,5/100=295 g NaCl
md1=10*1000/100=100 g NaCl
md transformat = 295 - 100 = 195 g NaCl
2 * 58,5 g NaCl........22,4 l H2......22,4 l Cl2
195 g NaCl................x l H2...........y l Cl2
x = y = 37,333 l H2 respectiv Cl2
=> V total = x+y=2*37,333=74,666 l