Răspuns:
[tex](12 \sqrt{3} - 5 \sqrt{3} ) \div 7 = 7 \sqrt{3} \div 7 \\ \sqrt{3} [/tex]
[tex]( - 12 \sqrt{15} + 12 \sqrt{15} ) \div ( - 6 \sqrt{5} = 0[/tex]
[tex]f)(8 \sqrt{5} + 24 \sqrt{5} - 20 \sqrt{5} ) \div \sqrt{5} = 12 \sqrt{5} \div \sqrt{5} = 12[/tex]
b)
[tex] - \frac{20 \sqrt{6 \times 3} }{6 } = \frac{60 \sqrt{2} }{6} = 10 \sqrt{3} [/tex]
[tex]d) \frac{3 \sqrt{3} }{29} \frac{3 \sqrt{6} - 8 \sqrt{6} }{12} = - \frac{15 \sqrt{9 \times 6} }{29 \times 12 } = \frac{45 \sqrt{6} }{348} [/tex]
[tex]f) \frac{5 \sqrt{2} }{3} ( \frac{8 \sqrt{10} - 5 \sqrt{10} }{30} ) = \frac{5 \sqrt{2} \times 3 \sqrt{10} }{3 \times 30} \\ = \frac{ \sqrt{2} \times \sqrt{10} }{6 } = \frac{2 \sqrt{5} }{6} = \frac{ \sqrt{5} }{3} [/tex]
