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9 la puterea logaritm in baza 3 din 4

Răspuns :

[tex] \huge\bf{9}^{ log_{3}(4) } = \\\huge\bf =( {3}^{2} ) {}^{ log_{3}( 4 ) } = \\ \huge \bf = 3 {}^{2 log_{3}( 4 ) } = \\\huge\bf= {3}^{ log_{3}( {4}^{2} ) } = {4}^{2} =\\\huge\bf= 16[/tex]