miu,CaCO3=100g/mol=100Kg/Kmol
miu,CaO=56g/mol=56kg/kmol
m= 5,6kgCaO
din ecuatia chimica, deduc masa de carbonat pur
1mol..........................1mol sau, in grame
CaCO3---> CaO + CO2
100kg..........56kg
x....................5,6kg
x=m=10kgCaCO 3PUR
din puritate, deduc masa de carbonat impur
p=m,px100/m,i= > m,i= 10x100/80kg=12,5kg carbonat impur