Răspuns:
[tex]a)2(x^{3} +3X^{2} +3X+1)-(x^{3} -4X^{2} +6X-2)=2 *x^{3} +2*3X^{2}+2* +3X+2*1 =2x^{3} +6X^{2} +6X+2-2*x^{3} -2*(-4X^{2} )+2*6X-2*(-2)=2x^{3} +8X^{2} +12X+4=2x^{3}+^{2} +6X+2-2x^{3} +8X^{2} +12X+4=(2x^{3} cu 2x^{3}....se - taie) =6X^{2} +6X+2-8X^{2} +12X+4=14X^{3}-24X^{4}=-10x[/tex]
cu pas: