notma arena mononucleara = CnH2n-6
=> 14n-6 = 92 => n = 7 => toluen
a) un CH3 legat de un inel aromatic (benzen)
b)
3,584 L n moli
C6H5-CH3 + Cl2 --lumina--> C6H5-CH2-Cl + HCl
22,4 1
=> n = 3,584x1/22,4 = 0,16 moli HCl
Cm = n/Vs => Vs = n/Cm = 0,16/0,1 = 1,6 L sol. HCl