[tex]\it a)\ \ =100\cdot(4+5\cdot9-32+64\cdot40:8)=100\cdot(4+45-32+320)=\\ \\ =100\cdot337=33700\\ \\ \\ b)\ \ =(2^{24}:2^3\cdot2\cdot2^6-2^{12}:2^{10}):(2^{28}-2^2)+9=\\ \\ =(2^{24-3+1+6}-2^{12-10}):(2^{28}-2^2)+9=(2^{28}-2^2):(2^{28}-2^2)+9=\\ \\ =1+9=10[/tex]
