Răspuns:
a) 2Fe + 3Cl2 → 2FeCl3 reactie de combinare
b)
MFeCl3=56+3×35,5=162,5g/mol
MFe=56g/mol
n=m/M
m=n×M=6×162,5=975g
2×56g................2×162,5g
2Fe + 3Cl2 → 2FeCl3
xg.......................975g
x=975×2×56/2×162,5=calculeaza
2moli.................2moli
2Fe + 3Cl2 → 2FeCl3
ymoli...............6moli
y=6×2/2= calculeaza
Explicație: