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3^22-3×(3^2+3^3)+6^0​

Răspuns :

Răspuns:

[tex]\bf 3^{22}-3\cdot (3^2+3^3)+6^0=[/tex]

[tex]\bf 3^{22}-3\cdot (9+27)+1=[/tex]

[tex]\bf 3^{22}-3\cdot 36+1= 3^{22}-3\cdot 36+1=[/tex]

[tex]\bf 3^{22}-108+1=\red{\underline{~3^{22}-107~}}[/tex]