a=|2x+3|-4|2-(2x=5)|=-27
|2x+3|-4x|2-2x-5|=-27
|2x+3|-4x|-3-2x|=-27
|2x+3|-4x|-3-2x|=-27
|2x+3|-4x|-3-2x|=-27
|2x+3|-4x|-3-2x|=-27
|2x+3|-4x|-(2x+3)|=-27
|2x+3|=4x|2x+3|=-27
|2x+3|=9
2x+3=9
2x+3=-9
[tex]x_{1}[/tex]=-6
[tex]x_{2}[/tex]=3
b)[tex]\frac{|x|-1}{4}-(\frac{|x|-2}{4}+\frac{7-2|x|}{5} \frac{|5x|-5}{10}-\frac{7}{4} =\frac{8x|x|-23}{20}[/tex]
[tex]\frac{|x|-1}{4}-\frac{5(|x|-2)+4(7-2x|x|)}{20}[/tex]
[tex]\frac{|x|-1}{4}-\frac{5x|x|-10+28-8x|x|}{20}[/tex]
[tex]\frac{|x|-1}{4}-\frac{-3x|x|+18}{20}[/tex]
[tex]\frac{5x|x|-5+3x|x|-18}{20}[/tex]
R=[tex]\frac{-11x|x|-62+3x^{2} }{40}[/tex]
Restul sunt scrise in fișierul atașat
