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√(√2−2√2)^(2)+(√3−3√3)^(2). dau coroana​

Răspuns :

Răspuns:

[tex] \sqrt{2} - 2 \sqrt{2} = ( - \sqrt{2} )[/tex]

[tex]( - \sqrt{2}) ^{2} = 2[/tex]

[tex] \sqrt{3} - 3 \sqrt{3} = ( - 2 \sqrt{3} )[/tex]

[tex]( - 2 \sqrt{3} ) ^{2} = 12[/tex]

[tex] \sqrt{2 + 12} = \sqrt{14} [/tex]