Răspuns: 136,86·10²³ molecule CO₂
Explicație pas cu pas:
[tex]p=1~atm\\\\T=273,15 K\\M_{CO_{2} }=12+2\cdot16=44~\frac{g}{mol}\\\nu=\frac{m_{CO_{2} }} {M_{CO_2}} =\frac{N_{CO_{2}}}{N_{A}}=>N_{CO_{2}}=\frac{m_{CO_{2}\cdot N_{A}} }{M_{CO_{2}}}=\frac{1000g*6,022*10^{23}\frac{molecule}{mol}}{44~\frac{g}{mol}}=136,86*10^{23}~molecule~CO_{2}[/tex]
