Răspuns:
1.I1={x∈Rl lxl≤5}
lxl≤5<=>
-5≤x≤5
I2=[-5,5]
Reuniunea
J2uI2=
[-5,5]U(0,3)=[-5,5]
I1∩I2=[-5,5]∩(0,3)=(0,3)
I1-I2=[-5,5]-(0,3)=[-5,0]U[3,5]
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2 .lxl>2=>
x>2 si x<-2
I1=(-∞,-2)U(2,+∞)
I1UI2=(-∞,-2)U(2,+∞)u[-1,1]=
(-∞,-2)U[-1,1]U(2,+∞)
I1∩I2=(-∞,-2)U(2,+∞)∩[-.1,1]=Ф
I1-I2=(-∞,-2)U(2,+∞)\[-1,1]=(-∞,-2)U(2,+∞)
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3)-2≤x<5<=.>
x∈[-2,5)=I1
I2 0<x<7
x∈(0,7)==I2
I1UI2=[-2,5)U(0,7)=[-2 7)
I1∩I2=[-2,5)∩(0,7)= (0,5)
I1-I2=[-2,5)-(0,7)=[-2,0]
Explicație pas cu pas:
