Răspuns:
[tex]a) \: (3x + 1) ^{2} - (x + 3) ^{2} = 9 {x}^{2} + 6x + 1 - ( {x}^{2} + 6x + 9) = 9 {x}^{2} + 6x + 1 - {x}^{2} - 6x - 9 = 8 {x}^{2} - 8[/tex]
[tex]b) = 9 {x}^{2} + 30x + 25 - ( {x}^{2} + 2x + 1) = 9 {x}^{2} + 30x + 25 - {x}^{2} - 2x - 1 = 8 {x}^{2} + 28x - 24[/tex]
[tex]c) {x}^{2} + 2x \sqrt{2} + 2 - 8 = {x}^{2} + 2 \sqrt{2} x - 6[/tex]
d)
[tex]4 {x}^{2} + 4 \sqrt{3} x + 3 - 27 = 4 {x}^{2} + 4 \sqrt{3} x - 24[/tex]
[tex]e) {2x}^{2} - 2 \sqrt{2} x + 1 - 32 {x}^{2} = - 30 {x}^{2} - 2 \sqrt{2} x + 1[/tex]
