Răspuns:
Explicație pas cu pas:
a)
[tex]|2-\sqrt{3} | + |1-\sqrt{3} | = 2-\sqrt{3} + \sqrt{3} - 1 = 1[/tex]
b)
[tex]|2-\sqrt{3} | +|\sqrt{5} +\sqrt{3} |+ |\sqrt{3}-2 | = 2-\sqrt{3} + \sqrt{5} +\sqrt{3} + 2-\sqrt{3} =4 + \sqrt{5} -\sqrt{3}[/tex]
c)
[tex]|\sqrt{2}+3 | + |\sqrt{2}-3 | = \sqrt{2}+3 + 3-\sqrt{2} = 6[/tex]
d)
[tex]2\sqrt{3} -3\sqrt{2} +2*|\sqrt{3}-2|+3*|\sqrt{2}-1| = \\2\sqrt{3} -3\sqrt{2} +2*(2-\sqrt{3})+3*(\sqrt{2}-1) = \\=2\sqrt{3} -3\sqrt{2} +4-2\sqrt{3}+3\sqrt{2}-3 = 1[/tex]
