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(2x-1)(2x+3)/2x+2=2x-1/3​

Răspuns :

Răspuns:

(2x-1)(2x+3)/2x+2=2x-1/3

3(4x^2+6x-2x-3)=(2x-1)(2x+1)

12x^2+12x-9=4x^2-1

8x^2+12x-8=0

Delta=b^2-4ac=144+4*64=144+256=400

x1=-12+20/16=8/16=1/2

X2=-12-20/16=-32/16=-2