[tex]x + y + z = 127 \\ 2 \times (x - 1) =y \\ z + 2 = 2 \times (x + y)[/tex]
[tex]2x - 2 = y \\ 2x = y + 2 \\x = \frac{y + 2}{2} [/tex]
[tex]z + 2 = 2 \times ( \frac{y + 2}{2} + y) \\ z + 2 = 2 \times \frac{y + 2 + 2y}{2} \\ z + 2 = 3y + 2 \\ z = 3y[/tex]
[tex] \frac{y + 2}{2} + y + 3y = 127 \\ \frac{y + 2 + 2y + 6y}{2} = 127 \\ \frac{9y + 2}{2} = 127 \\ 9y + 2 = 254 \\ 9y = 252 \\ y = 28 \\ x =15 \\ z =84[/tex]
