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daca x si y sunt invers proportionale cu 5 si 3, atunci 3x+4y/5x-2y

Răspuns :

[tex] \frac{x}{5} = \frac{y}{3} = k[/tex]

[tex]x = 5k[/tex]

[tex]y = 3k[/tex]

[tex] \frac{3x + 4y}{5x - 2y} = \frac{3 \times 5k + 4 \times 3k}{5 \times 5k - 2 \times 3k} = \frac{15k + 12k}{25k - 6k} = \frac{27k}{19k} = \frac{27}{19} [/tex]