Exercițiul 4)
[tex] \bf a = \dfrac{^{2)} 5 \: }{36} + \dfrac{^{3)} 1 \: }{24} = \dfrac{10 + 3}{72} \implies \green{ a= \dfrac{13}{72}} [/tex]
[tex] \bf [/tex]
[tex] \bf b = \dfrac{^{2)} 5 \: }{12} + \dfrac{1}{24} = \dfrac{10 + 1}{24} \implies \blue{ b= \dfrac{11}{24}} [/tex]
[tex] \bf [/tex]
[tex] \bf c = \dfrac{^{3)} 5 \: }{48} + \dfrac{^{4)} 1 \: }{36} = \dfrac{15+4}{144} \implies \purple{c= \dfrac{19}{144}} [/tex]
[tex] \bf [/tex]
[tex] \bf a + b =\dfrac{13}{72}+\dfrac{^{3)} 11}{24} =\dfrac{13+33}{72} = \dfrac{46^{(2}}{72} \implies \red{a + b\dfrac{23}{36}} [/tex]
[tex] \bf [/tex]
[tex] \bf a+c =\dfrac{^{2)}13 \:}{72}+\dfrac{19}{144} =\dfrac{26+19}{144}=\dfrac{45^{(9}}{144} \implies \red{a+c = \dfrac{5}{16}} [/tex]
[tex] \bf [/tex]
[tex]\bf a+b + c=\dfrac{^{2)}13\:}{72}+ \dfrac{^{6)}11\:}{24} + \dfrac{19}{144} =\dfrac{26+66+19}{144}=\dfrac{111^{(3}}{144} \implies \red{a+b+c=\dfrac{37}{48}}[/tex]
P.S.: Dacă ești pe telefon te rog să glisezi spre stânga pentru a vedea întreaga rezolvare.
Baftă multă !
