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(Radical din3-1)(radical din 6+2)

Răspuns :

Răspuns:

[tex]( \sqrt{3} - 1)( \sqrt{6} + 2) = \sqrt{18} + 2 \sqrt{3} - \sqrt{6} - 2[/tex]

[tex] = 3 \sqrt{2} + 2 \sqrt{3} - \sqrt{6} - 2[/tex]

Salut!

(√3-1)(√6+2)=

=√18+2√3-√6-2

=3√2+2√3-√6-2

Succes!