Răspuns:
Mamidon=162n, g/mol
M,glucoza=180g/mol
p=80%
p=m,px100/m,i---> m,p=20,25x80/100kg= 16,2kg amidon pur
reactia este
(C6H10O5)n + (n-1) H2O-> nC6H12O6
162n, kg amidon...........180n,kg glucoza
16,2kg.......................................x
x= 18kg glucoza
Explicație: