Răspuns:
[tex]AB=4[/tex]
[tex]AC=3[/tex]
[tex]m(A)=30^*[/tex]
[tex]BC^2=AC^2+AB^2-2AC*AB*cos(A)[/tex]
[tex]BC^2=9+16-2*3*4*cos(30)=25-24*\frac{\sqrt{3} }{2} =25-12\sqrt{3}[/tex]
[tex]BC=\sqrt{25-12\sqrt{3} }[/tex]
Perimetrul [tex]= AC+AB+BC=7+\sqrt{25-12\sqrt{3} }[/tex]