Răspuns:16.2gAl; 0,04litri clor
Explicație:2Al +3Cl2= 2 AlCl3
AlCl3 +3 NaOH= Al(OH)3 +3NaCl
2Al(OH)3-------->Al2O3 +3H2O
a) MAl2O3=102---->n=30,6/102=0,3 moli Al2O3
1molAl2O3--2moli Al(OH)3
0,3---------------0,6 moli
1mol AL(oh)3-----1mol AlCl3
0.6-------------------0.6moli
2moliAlCl3-------2moli Al
0.6moli-----------0.6moli Al
n=m/M=> m=n.M=0.6 . 27=16.2g Al
b) 2moli Al------3moli Cl2
0.6moli Al---xmoli Cl2
x=0.9moli Cl2
V=n/V0=0.9/22.4=0.04LITRI Cl2