Răspuns:
(4m²-1)²x²+4mx+1=0
△ = b²-4ac
△ = (4m)²-4×(4m²-1)×1
△ = 16m²-16m²+4
△ =4
△ = 2²
x1=(-4m-√4)/[2×(4m²-1)]
x1=(-4m-2)/[2×(4m²-1)]
x1=2(-2m-1)/[2(4m²-1)]
x1=(-2m-1)/(4m²-1)
x1=-(2m+1)/[(2m-1)(2m+1)]
x1=-1/(2m-1)
x2=(-4m+√4)/[2×(4m²-1)]
x2=(-4m+2)/[2(2m-1)(2m+1)]
x2=-2(2m-1)/[2(2m-1)(2m+1)]
x2=-1/(2m+1)
