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fie dezvoltarea: (rad2 + 2^1/3)^60; demonstrati ca T13 apartine N

Răspuns :

[tex]\it (\sqrt2+2^{\frac{1}{3}})^{60}\\ \\ T_{13}=T_{12+1}=\Big C_{60}^{12} (\sqrt2)^{48}\cdot(2^{\frac{1}{3}})^{12}=\Big C_{60}^{12} 2^{24}\cdot2^{4}=\Big C_{60}^{12} \cdot 2^{28}\in\mathbb{N}[/tex]