VA ROOGGG E URGEENTTT!!!!!!!!
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Răspuns:
Explicație pas cu pas:
d) -x<0-2
-x<-2
x>2 => x∈(2,+∝)
h) -2x+10≤0
-2x≤0-10
-2x≤-10
x≤[tex]\frac{-10}{-2}[/tex]
x≤5 => x∈(-∝,5]
l) -4x≥-12
x≥[tex]\frac{-12}{-4}[/tex]
x≥3 => x∈[3,+∝)