Răspuns: [tex] \red{\large\boxed{\bf a = \dfrac{16}{15} }}[/tex]
Explicație pas cu pas:
[tex]\large\bf a=\bigg(\!{^{^{^{^{^{^{\displaystyle 5)}}}}}}}\!\!\!\dfrac{1}{3}+ \!{^{^{^{^{^{^{\displaystyle 3)}}}}}}}\!\!\!\dfrac{1}{5}\bigg):\dfrac{1}{2} [/tex]
[tex]\large\bf a=\bigg(\dfrac{5}{15}+ \dfrac{3}{15}\bigg)\cdot\dfrac{2}{1}\implies a=\dfrac{5+3}{15}\cdot\dfrac{2}{1}[/tex]
[tex]\large\bf a=\dfrac{8}{15}\cdot\dfrac{2}{1}\implies \red{\boxed{\bf a = \dfrac{16}{15} \longrightarrow~adevarat}}[/tex]
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[tex]\large\bf b=\dfrac{1}{2} \cdot\bigg(\!{^{^{^{^{^{^{\displaystyle 5)}}}}}}}\!\!\!\dfrac{1}{3}- \!{^{^{^{^{^{^{\displaystyle 3)}}}}}}}\!\!\!\dfrac{1}{5}\bigg)[/tex]
[tex]\large\bf b=\dfrac{1}{2}\cdot\bigg(\dfrac{5}{15}- \dfrac{3}{15}\bigg)\implies b=\dfrac{1}{2}\cdot\dfrac{5-3}{15}[/tex]
[tex]\large\bf b=\dfrac{1}{\not2}\cdot\dfrac{\not2}{15}\implies \pink{\boxed{\bf b = \dfrac{1}{15} }}[/tex]
PS: Daca esti pe telefon te rog sa glisezi spre stânga pentru a vedea întreaga rezolvare.
Baftă multă!
#copaceibrainly
