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(1+1/3÷2 intregi si 2/3)³÷(-9/8)³+1



Răspuns :

Răspuns:

2 intregi si 2/3=(2·3+2)/3=8/3

(1+1/3:8/3)³:(-9/8)³+1=

(1+1/3·3/8)³:(-9/8)³+1=

(⁸⁾1+1/8)³:(-9/8)³+1=

(9/8)³:(-9/8)³+1=(-9/8)³⁻³+1=-1+1=0