Răspuns:
c)
[tex](5 \frac{2}{3} + 1(5) - 2) \div 15\frac{2}{3}
1.
[tex]5 \frac{2}{3} + \frac{15}{9} = \frac{17}{3} + \frac{15}{9} = \frac{51}{9} + \frac{15}{9} = \frac{66}{9} = 7 \frac{1}{3} [/tex]
2.
[tex]7 \frac{1}{3} - 2 = 5 \frac{1}{3} [/tex]
3.
[tex]5 \frac{1}{3} \div 15 \frac{2}{3} = \frac{16}{3} \div \frac{47}{3} = \frac{16}{3} \times \frac{3}{47} = \frac{16}{47} [/tex]
d)
[tex](4 + 6 \frac{2}{3} - 2 \frac{1}{4} \times ( \frac{2}{3} - \frac{2}{9} )) \div \frac{5}{6} + \frac{29}{4} [/tex]
1.
[tex] \frac{2}{3} - \frac{2}{9} = \frac{6}{9} - \frac{2}{9} = \frac{4}{9} [/tex]
2.
[tex]4 + 6 \frac{2}{3} - \frac{9}{4} \times \frac{4}{9} = 4 + 6 \frac{2}{3} - 1 = 3 + 6 \frac{2}{3} = 9 \frac{2}{3} [/tex]
3.
[tex]9 \frac{2}{3} \div \frac{5}{6} = \frac{29}{3} \times \frac{6}{5} = \frac{29 \times 2}{5} = \frac{58}{5} [/tex]
4.
[tex] \frac{58}{5} + \frac{29}{4} = \frac{232}{20} + \frac{145}{20} = \frac{377}{20} = 18 \frac{17}{20} [/tex]
