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Rezolvati in r ecuația (x+5) (x+2)-3(4x-3)=(x-5 ) pătrat ​

Răspuns :

Răspuns: [tex]\color{orangered}\Large\boxed{\bf x=\dfrac{6}{5} }[/tex]

Explicație pas cu pas:

[tex]\large\bf (x+5)\cdot (x+2)-3\cdot(4x-3)=(x-5 )^{2}[/tex]

[tex]\large\bf x^{2} +2x+5x+10 -3\cdot(4x-3)=(x-5 )^{2}[/tex]

[tex]\large\bf x^{2} +7x+10 -12x +9=(x-5 )^{2}[/tex]

[tex]\large\bf x^{2} +7x+10 -12x +9=x^{2} -10x+25[/tex]

[tex]\large\bf x^{2} -5x+19 =x^{2} -10x+25[/tex]

[tex]\large\bf x^{2} -5x+19 -x^{2} +10x=25[/tex]

[tex]\large\bf 5x+19=25[/tex]

[tex]\large\bf 5x=25 -19[/tex]

[tex]\large\bf 5x=6[/tex]

[tex]\color{red}\Large\boxed{\bf x=\dfrac{6}{5} ~~sau~ ~x=1\dfrac{1}{5}}[/tex]

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