Răspuns:
a) 3*(x^2-4x+4)=2x+4
3x^2-12x+12-2x+4=0
3x^2-14x+16=0
delta=(-14)^2-4*3*16=4
x1=[-(-14)-√4]/2*3=2
x2=[-(-14)+√4]/2*3=16/6=8/3
b) (x+2)^2=x*(3x+2)
x^2+4x+4=3x^2+2x
x^2-3x^2+4x-2x=0
-2x^2+2x=0
-2x(x-1)=0
x=0 sau x-1=0
x=1
d) (3x-2)*(x+6)=-9
3x^2+18x-2x-12+9=0
3x^2+16x-3=0
delta=16^2-4*(-3)*3=292
x1=(-16-√192)/2*3=(-16-4√73)/6=(-8-2√73)/3
x2=(-8+2√73)/3
e) (x+2)^2=8*(3x+8)
x^2+4x+4=24x+64
x^2+4x+4-24x-64=0
x^2-20x-60=0
delta=(-20)^2-4*(-60)=160
x1=[-(-20)-√160]/2=(20-4√10)/2=10-2√10
x2=[-(-20)+√160]/2=(20+4√10)/2=10+2√10
Explicație pas cu pas:
Succes
