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apriciez maxim raspunsu

Apriciez Maxim Raspunsu class=

Răspuns :

Problema 1:

L=16cm

d=32cm

L²+l²=d²

16²+l²=32²

l²=32²-16²

l²=(32-16)(32+16)

l²=16*48

l=16*rad(3)

A=l*L=16rad3*16=256rad3 cm²

Problema 2:

l=10cm

P=32cm

A=?

P=2l+b (l=latura egala, b baza)

P=20+b=32

b=12cm

A (heron)=rad((p-a)(p-b)(p-c))=rad(16-12)(16-10)(16-10))

A=rad(4*6²)=2*6=12cm²

Problema 3:

P=52cm

d=24cm

P=4l=52cm

l=13cm (latura rombului)

(dm/2)²+(d/2)²=l² (dm diagonala mica, d diag mare)

(dm/2)²+12²=13²

(dm/2)²=(13-12)(13+12)

(dm/2)²=25

dm/2=5

dm=10cm

A=dm*d/2=10*13/2=5*13=65cm²

Problema 4 nu am cum sa o rezolv

Problema 5

b=4m

B=10m

alfa=45*

mvopsea=2kg

Arie/masa=1m²/80g

daca alfa=45*, atunci h=B-b

A=(B+b)h/2=14*6/2=42m²

Arie/masa*mvopsea=2000/80=25m² vopsea

25m²<42m² (Nu avem destula vopsea)