Răspuns:
Teorema lui Pitagora:
BC la patrat = AC la patrat + AB la patrat
BC la Patrat = 36 + 36*3
BC la patrat = 36*4
BC = radical (36*4)
BC = 6*2
BC = 12
Sin C = AB/BC
Sin C = 6/12
Sin C = 1/2
Masura lui C = 30 grade
Masura lui B = 180- masura A - masura C
Masura lui B = 180-90-30
Masura lui B = 60 grade
Triunghiul ABD, cu masura D =90 grade, masura B =60 grade
Cos B = AD/ AB
Radical3/2=AD/ 6
AD=6radical3 /2
AD=3 radical3
Sin B = BD/AB
1/2=BD/ 6rad3
BD = 6rad3 /2
BD = 3 rad3
Triunghiul ADC dreptunghic in D
Cos C =DB/AC
Cos 30=DB/ 6rad3
Rad3 /2 = DB/ 6rad3
DB = (rad3 * 6 rad 3)/2
DB = 6*3/2
DB= 9
P = 6 + 6rad3 + 12 = 18 + 6 rad 3 = 6(3+rad3)
A= AB*AC/2
A = 6 * 6 rad3 /2
A= 18 rad3
