Răspuns:
AB=c=2
AC=b=2√3
<B=π/3
-------------------------------
<C=?
Aplici teorema sinusului
c/sin C=b/sin <B
2/sinc=2√3/sinπ/3
2/sinC=2√3/(√3)/2
2/sinC=2*2
2sinC=4
sinC=4/2=1/2=>
<C=π/6=>
<A=π-(π/3+π/6)=
π-3π/6=π-π/2=π/2
Triunghiul ABC dreptunghic in A
Aplici Pitagora
a²=b²+c²
a²=(2√3)²+2²=
4*3+4=16
a=√16
a=4
BC=4
Explicație pas cu pas:
