VA ROG IMI TREBUIE IN 10 MINUTE SI NU MAI AM TIMP PENTRU TOT!! DAU 30 PCT!!
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[tex]\it x=-2 \Rightarrow\ raportul\ devine\ :\\ \\ \dfrac{(-2)^3+7\cdot(-2)}{3\cdot(-2)-2}=\dfrac{-8-14}{-6-2}=\dfrac{-22}{-8}=\dfrac{\ 22^{(2}}{8}=\dfrac{11}{4}[/tex]