1. MCH4 = AC +4AH= 12+4=16 g/mol
1 mol ....................... 16 g CH4
nCH4 ........................... 50 g CH4
nCH4= (1*50)/16 = 50/16=3,125 moli
2. 1 mol.......22,4 L SO2
n moli...... 44,8 L SO2
n=44,8/22,4=2 moli SO2
3. 1 mol H2.............6, 023 •10²³ molecule
x moli H2............ 2,3• 10²³ molecule
x=1*2,3•10²³ /6,023•10²³=0,38 moli H2
Sper că te-am ajutat!