Salut,
Știm formula generală:
[tex](x^n)\ ^{'}=n\cdot x^{n-1}.[/tex]
[tex]f(x)=x^2+\dfrac{1}{x^2}=x^2+x^{-2}.\\\\f\ ^{'}(x)=2\cdot x^{2-1}+(-2)\cdot x^{-2-1}=2x-2\cdot x^{-3}=2x-\dfrac{2}{x^3}.\\\\Deci\ f\ ^{'}(x)=2x-\dfrac{2}{x^3}.[/tex]
Ai înțeles ?
Green eyes.
