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In triunghiul ABC consideram punctul E ∈ (MN) si construim EF║BC,F ∈ (AC).Daca:
a)AE=2 cm,EB=4 cm si AF=3 cm,aflati FC
b)EB=3 cm,AF=3 cm si FC=9 cm,aflati AE
c)AE=5 cm,AB=20 cm si AF=10 cm,aflati AC
d)AB=18 cm,AF=7 cm si AC=21 cm,aflati AE
e)EB=2 cm,AB=10 cm si AC= 15 cm,aflati FC
f)AC=25 cm,FC=15 cm si EB=9 cm,aflati AB
Va rog!daca vreti fiecare in parte


Răspuns :

) 2•FC=3•4

2•FC=12

FC=12:6

FC=2

b) 3•AE=3•9

3•AE=27

AE=27:3

AE=9

c) 5•AC=20•10

5•AC=200

AC=200:5

AC=40

la restul faci acelasi lucru