Răspuns:
a) [tex]x^{2}[/tex]=4 -> x=2, x=-2
b) [tex]x^{2}[/tex]-3=0 ->
c) [tex](x-1)^{2}[/tex]=0
scoatem radacina patrata:
x-1=0 -> x=1
d) [tex](x-\sqrt{2})^{2}[/tex] - 8 = 0 ->
scoatem radacina patrata:
[tex]x-\sqrt{2}[/tex]= [tex]2\sqrt{2}[/tex] -> x=[tex]3\sqrt{2}[/tex]
e) 2[tex]x^{2}[/tex] - 3 = 4 -> 2
scoatem radacina patrata:
x= [tex]\frac{\sqrt{7}}{\sqrt{2}} =\frac{\sqrt{14}}{2}[/tex]
f) [tex]x^{2}[/tex] + 1 = 0
[tex]x^{2}[/tex] = -1, dar stim ca orice numar ridicat la patrat este pozitiv ( [tex]\geq0[/tex]), deci:
x∈∅
