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scrieti ca puteri cu acelasi exponenent( 1/3)la 26 si (1/4)la 39 , (6 1/4)la 48 si (3 1/2 )la 96 , (1/9)la 18 si (5/3)la 36

Răspuns :

Răspuns: Ai rezolvarea mai jos

Explicație pas cu pas:

Salutare!

[tex]\large\ast~~\bf \Bigg(\dfrac{1}{4} \Bigg)^{39}=\Bigg(\dfrac{1}{2^{2}} \Bigg)^{39}= \dfrac{1}{2^{2\cdot 39}}= \dfrac{1}{2^{78}}=\Bigg(\dfrac{1}{2^{3}} \Bigg)^{26}=\boxed{\bf \Bigg(\dfrac{1}{8} \Bigg)^{26}}[/tex]

[tex]\large\ast~~\bf \bf \Bigg(\dfrac{1}{3} \Bigg)^{26}[/tex]

                                                             

[tex]\large\ast~~\bf \Bigg(6\dfrac{1}{4} \Bigg)^{48}=\Bigg(\dfrac{25}{4} \Bigg)^{48}= \Bigg(\dfrac{5^{2}}{2^{2}}\Bigg)^{48}= \dfrac{5^{2\cdot48}}{2^{2\cdot48}}=\boxed{\bf \Bigg(\dfrac{5}{2} \Bigg)^{96}}[/tex]

[tex]\large\ast~~ \bf \Bigg(3\dfrac{1}{2} \Bigg)^{96}= \Bigg(\dfrac{7}{2} \Bigg)^{96}[/tex]

                                                             

[tex]\large\ast~~\bf \Bigg(\dfrac{1}{9} \Bigg)^{18}= \Bigg(\dfrac{1^{2}}{3^{2}}\Bigg)^{18}= \dfrac{1^{2\cdot18}}{3^{2\cdot18}}=\dfrac{1^{36}}{3^{36}}=\boxed{\bf \Bigg(\dfrac{1}{3} \Bigg)^{36}}[/tex]

[tex]\large\ast~~\bf \Bigg(\dfrac{5}{3} \Bigg)^{36}[/tex]

PS: Daca esti pe telefon, te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa

==pav38==

Răspuns:

Rezolvarea mea este in atașament.......

Vezi imaginea Аноним