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a) 64g O=.. .........moli O=.........atomi O
b) ...moli Mg=............g Mg= 18,066x1023 atomi Mg
atomi o

dau coroana mă jur​


Răspuns :

Răspuns:

nr moli= masa/Masa moleculara

nr atomi= nr moli*6.022*10²³

masa=nr moli*Masa moleculara

a)Masa moleculara O2=2*16=32g/mol

64 g O2=64/32=2 moli O2=2*6.022*10²³ =12.044*10²³ atomi O2

b)Masa molecula Mg=24g/mol

18.066*10²³ atomi Mg=(18.066*10²³)/(6.022*10²³)=3 moli Mg =3*23=69g Mg