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Se neutralizeaza 200g solutie hidroxid de sodiu de concentratie 40% cu solutie de acid clorhidric de concentratie 36.5%. Ce concentratie va avea solutia obtinuta?

Răspuns :

NaOH + HCl ---> NaCl + H2O
c NaOH = md NaOH/ms NaOH * 100=>md NaOH = 200*40/100=80 g NaOH
40 g NaOH........36,5 g HCl
80 g NaOH..........x g HCl        x = 73 g HCl = md
ms HCl = md HCl/c HCl * 100 = 73/36.5*100=200 g solutie
ms final = 200+200=400 g
md final = 80 + 73 = 153 g
c% finala = 153/400*100=>c%=38.25%