Explicație pas cu pas:
[tex]1.x {}^{2} = 7 + 4 \sqrt{3} \\ x {}^{2} = 7 {}^{2} +( 4 \sqrt{3} ) {}^{2} \\ x {}^{2} = 49 + 48\\ x {}^{2} = 92\\ x = \sqrt{92} \\ \\ 2.x {}^{2} = 4 - 2 \sqrt{3} \\ x {}^{2} = 4 {}^{2} - (2 \sqrt{3} ) {}^{2} \\ x {}^{2} = 16 - 8 \\ x {}^{2} = 8 \\ x = \sqrt{8} \\ x = 2 \sqrt{2} [/tex]
