5. Multimea A
D (14) = 1, 2, 7, 14
=> 2x +1 = 1, 2, 7, 14
=> 2x = 0, 1 (nu convine), 6 , 13 (nu convine)
=> A = ( 0 si 3 )
Multimea B
(3X + 5 / 2 X + 1 ) + 1
3 X x 2 / 2 X x 2
simplificam 2 x X => 3 / 2 = 3 jumatati
Multiplii comuni 2 si 3: 6, 12, 18, 24, 30 ...
6 : 3 jum. / 2 = 1 unitate => convine
12 : 3 jum / 2 = 2 unitati , 12 : 2 = 6
A = (Multiplii 2 si 3)
Multimea C
x = toate nr cuprinse intre 51 si 61
A = ( 60, 59, 58, 57, 56, 55, 54, 53, 52)
Multimea D
(5 / 6 ) x 2 <sau egal X + 1 / 12 < ( 5 / 4 ) x 3
=> 10 / 12 <sau egal X + 1 / 12 < 15 / 12
=> X = 9, 10, 11, 12, 13
6. Deocamdata nu stiu, scz
7. ab0 - ab = 10 x ab - 1x ab = 9 x ab
9 x ab / 9 = ab
