Răspuns:
3.
H2+Cl2=> 2HCl
2Li+ Cl2=> 2LiCl
2Ba+Cl2 => BaCl2
2Fe+ 3Cl2 =>2 FeCl3
4.
NCl2 =2×35,5=71g/mol
m=4×71=284g
MLiCl=7+35,5+7=42,5g/mol
71g 2×42,5g
2Li+ Cl2=> 2LiCl
284g xg
x=284×2×42,5/71=calculează
MBaCl2=137+2×35,5=208g/mol
71g 208g
2Ba+Cl2 => BaCl2
284g yg
y=284×207/71=calculează
MFeCl3= 56+3×35,5=162,5g/mol
3×71g 2×162,5g
2Fe+ 3Cl2 =>2 FeCl3
284g zg
z=284×2×162,5/3×71=calculează